Presentation on theme: "Turning Moment Diagram"— Presentation transcript:
1 Turning Moment Diagram
GANDHINAGAR INSTITUTE OF TECHNOLOGY Presentation on Turning Moment Diagram THEORY OF MACHINES Guided By : Mr. Mehul V. Kodia Submitted by : Kapadiya Kalapi D.( ) Vyas Bhavin M.( ) LJ INSTITUTE OF ENGINEERING AND TECHNOLOGY
2 Contents Introduction
Turning Moment Diagram for a Single Cylinder Double Acting Steam Engine Turning Moment Diagram for a Four Stroke Cycle Internal Combustion Engine Turning Moment Diagram for a Multi cylinder Engine Fluctuation of Energy Determination of Maximum Fluctuation of Energy Coefficient of Fluctuation of Energy
3 Introduction The turning moment diagram is the graphical representation of the turning moment or crank-effort for various positions of the crank. Hence, it is also known as crank effort diagram. It is plotted on Cartesian co-ordinates, in which the turning moment is taken as the ordinate and crank-angle as abscissa.
4 Turning Moment Diagram for a Single Cylinder Double Acting Steam Engine
5 We know that the turning moment on the crankshaft is
where FP = Piston effort, r = Radius of crank, n = Ratio of the connecting rod length and radius of crank, and = Angle turned by the crank from inner dead centre.
6 From the above expression, we see that the turning moment (T ) is zero, when the crank angle () is zero. It is maximum when the crank angle is 90° and it is again zero when crank angle is 180°. This is shown by the curve abc in Fig and it represents the turning moment diagram for outstroke. The curve cde is the turning moment diagram for instroke and is somewhat similar to the curve abc. Since the work done is the product of the turning moment and the angle turned, therefore the area of the turning moment diagram represents the work done per revolution.
7 Turning Moment Diagram for a Four Stroke Cycle Internal Combustion Engine
8 Since the pressure inside the engine cylinder is less than the atmospheric pressure during the suction stroke, therefore a negative loop is formed as shown in Fig. During the compression stroke, the work is done on the gases, therefore a higher negative loop is obtained. During the expansion or working stroke, the fuel burns and the gases expand, therefore a large positive loop is obtained. In this stroke, the work is done by the gases. During exhaust stroke, the work is done on the gases, therefore a negative loop is formed. It may be noted that the effect of the inertia forces on the piston is taken into account in Fig.
9 Turning Moment Diagram for a Multi cylinder Engine
10 A separate turning moment diagram for a compound steam engine having three cylinders and the resultant turning moment diagram is shown in Fig. The resultant turning moment diagram is the sum of the turning moment diagrams for the three cylinders. It may be noted that the first cylinder is the high pressure cylinder, second cylinder is the intermediate cylinder and the third cylinder is the low pressure cylinder. The cranks, in case of three cylinders, are usually placed at 120° to each other.
11 Fluctuation of Energy The fluctuation of energy may be determined by the turning moment diagram for one complete cycle of operation. Consider the turning moment diagram for a single cylinder double acting steam engine as shown in Fig.
12 We see that the mean resisting torque line AF cuts the turning moment diagram at points B, C, D and E. When the crank moves from a to p, the work done by the engine is equal to the area aBp, whereas the energy required is represented by the area aABp. In other words, the engine has done less work (equal to the area a AB) than the requirement. This amount of energy is taken from the flywheel and hence the speed of the flywheel decreases. Now the crank moves from p to q, the work done by the engine is equal to the area pBbCq, whereas the requirement of energy is represented by the area pBCq. Therefore, the engine has done more work than the requirement. This excess work (equal to the area BbC) is stored in the flywheel and hence the speed of the flywheel increases while the crank moves from p to q.
13 Similarly, when the crank moves from q to r, more work is taken from the engine than is developed. This loss of work is represented by the area CcD. To supply this loss, the flywheel gives up some of its energy and thus the speed decreases while the crank moves from q to r. As the crank moves from r to s, excess energy is again developed given by the area D d E and the speed again increases. As the piston moves from s to e, again there is a loss of work and the speed decreases. The variations of energy above and below the mean resisting torque line are called fluctuations of energy. The areas BbC, CcD, DdE, etc. represent fluctuations of energy.
14 The engine has a maximum speed either at q or at s.
This is due to the fact that the flywheel absorbs energy while the crank moves from p to q and from r to s. On the other hand, the engine has a minimum speed either at p or at r. The reason is that the flywheel gives out some of its energy when the crank moves from a to p and q to r. The difference between the maximum and the minimum energies is known as maximum fluctuation of energy.
15 Determination of Maximum Fluctuation of Energy
A turning moment diagram for a multi- cylinder engine is shown by a wavy curve in Fig.
16 The horizontal line AG represents the mean torque line
The horizontal line AG represents the mean torque line. Let a1, a3, a5 be the areas above the mean torque line and a2, a4 and a6 be the areas below the mean torque line. These areas represent some quantity of energy which is either added or subtracted from the energy of the moving parts of the engine.
17 Let the energy in the flywheel at A = E, then from Fig, we have
Energy at B = E + a1 Energy at C = E + a1– a2 Energy at D = E + a1 – a2 + a3 Energy at E = E + a1 – a2 + a3 – a4 Energy at F = E + a1 – a2 + a3 – a4 + a5 Energy at G = E + a1 – a2 + a3 – a4 + a5 – a6 = Energy at A (i.e. cycle repeats after G) Let us now suppose that the greatest of these energies is at B and least at E.
18 Therefore, Maximum energy in flywheel = E + a1
Minimum energy in the flywheel = E + a1 – a2 + a3 – a4 Maximum fluctuation of energy, E = Maximum energy – Minimum energy = (E + a1) – (E + a1 – a2 + a3 – a4) = a2 – a3 + a4
19 Coefficient of Fluctuation of Energy
It may be defined as the ratio of the maximum fluctuation of energy to the work done per cycle. Mathematically, coefficient of fluctuation of energy, The work done per cycle (in N-m or joules) may be obtained by using the following two relations :
20 1. Work done per cycle = Tmean × where Tmean = Mean torque, and = Angle turned (in radians), in one revolution. = 2, in case of steam engine and two stroke internal combustion engines = 4, in case of four stroke internal combustion engines. The mean torque (Tmean) in N-m may be obtained by using the following relation : where P = Power transmitted in watts, N = Speed in r.p.m., and = Angular speed in rad/s = 2N/60
21 2. The work done per cycle may also be obtained by using the following relation : Work done per cycle = (P x 60)/n where n = Number of working strokes per minute, = N, in case of steam engines and two stroke internal combustion engines, = N/2, in case of four stroke internal combustion engines.
22 The following table shows the values of coefficient of fluctuation of energy for steam engines and internal combustion engines.
23 THANK YOU!
24 References Theory of Machines, 14th ed. - Khurmi, R.
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